Signed-off-by: big <1638587056@qq.com>
This commit is contained in:
commit
d2a22c0249
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# 默认忽略的文件
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/shelf/
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/workspace.xml
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<component name="InspectionProjectProfileManager">
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<settings>
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<option name="USE_PROJECT_PROFILE" value="false" />
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<version value="1.0" />
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</settings>
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</component>
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<?xml version="1.0" encoding="UTF-8"?>
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<project version="4">
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<component name="ProjectRootManager" version="2" project-jdk-name="Python 3.10 (2)" project-jdk-type="Python SDK" />
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</project>
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<?xml version="1.0" encoding="UTF-8"?>
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<project version="4">
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<component name="ProjectModuleManager">
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<modules>
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<module fileurl="file://$PROJECT_DIR$/.idea/python程序.iml" filepath="$PROJECT_DIR$/.idea/python程序.iml" />
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</modules>
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</component>
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</project>
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<?xml version="1.0" encoding="UTF-8"?>
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<module type="PYTHON_MODULE" version="4">
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<component name="NewModuleRootManager">
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<content url="file://$MODULE_DIR$">
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<excludeFolder url="file://$MODULE_DIR$/venv" />
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</content>
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<orderEntry type="jdk" jdkName="Python 3.10 (2)" jdkType="Python SDK" />
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<orderEntry type="sourceFolder" forTests="false" />
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</component>
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</module>
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#插入排序
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num = [13,2,8,12,1,456,89]
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for i in range(1,len(num)):
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key = num[i] #获取未排序部分的第一项值
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j = i-1 #设置已排序部分的最后一位编号
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print("需要插入的值:", key)
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while j>=0 and num[j]<key:
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num[j+1] = num[j]
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j -= 1
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print(key,"放在了第",j+1)
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num[j+1] = key
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print(num)
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'''
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(n-1)*(n-1)
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=n*n - n*1 - 1*n + 1*1
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=n*n - 2*n + 1
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时间复杂度 O(n^2)
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'''
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d1 = {"a":10,"b":20,"c":2,"d":7,"e":6}
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l1 = list(d1)
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for j in range(len(l1) - 1):
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for i in range(len(l1) - 1):
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if d1[l1[i]] > d1[l1[i+1]]:
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d1[l1[i]],d1[l1[i+1]] = d1[l1[i+1]],d1[l1[i]]
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print(d1)
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import sys
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import pygame
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#初始化pygame
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pygame.init()
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#初始化显示
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pygame.display.init()
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#创建显示窗口
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sc = pygame.display.set_mode((400,300))
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#创建时钟对象
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clock = pygame.time.Clock()
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#设置变量运行游戏为真
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is_running = True
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#砖块初始化
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zk_x = 7.5#第一块转的x坐标
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zk_y = 5#第一块转的y坐标
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zk_w = 30#砖块的宽度
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zk_h = 10#砖块的高度
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zk_list = []#初始化砖块列表
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#行
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for j in range(4):
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#列
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for i in range(11):
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r = pygame.Rect(zk_x,zk_y,zk_w,zk_h)#创建砖块的矩形区域
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zk_list.append(r)#将矩形区域加入列表中
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zk_x += 35#更新x坐标
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zk_y += 15#更新y坐标
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zk_x = 7.5#重置x坐标
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ballx = 200#小球的x坐标
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bally = 150#
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ball_speed_x = 2#
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ball_speed_y = 2#
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#游戏主循环
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while is_running:
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#背景填充黑色
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sc.fill("black")
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#遍历砖块列表
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for z in zk_list:
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#绘制砖块
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pygame.draw.rect(sc,"white",z)
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ball = pygame.draw.circle(sc, "white", (ballx, bally), 5)
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ballx = ballx + ball_speed_x
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bally = bally + ball_speed_y
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if ballx > 395 or ballx < 5 :
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ball_speed_x = -ball_speed_x
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if bally > 295 or bally < 5 :
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ball_speed_y = -ball_speed_y
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#遍历事件
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for event in pygame.event.get():
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#如果事件为退出事件
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if event.type == pygame.QUIT:
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is_running = False
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pygame.display.flip()#显示更新
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clock.tick(60)#设置更新帧率为60
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pygame.quit()#结束pygame初始化
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sys.exit()#结束系统进程
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h = int(input())
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m = int(input())
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s = int(input())
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k = int(input())
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s += k
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if s >= 60:
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s = s-60
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m += s//60
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s = s%60
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if m >= 60:
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h += m//60
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m = m%60
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print(h,m,s)
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# 循环变量,用于记录每一次循环的数据
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# 0 <= a < 100\
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l1 = [12,45,67,89,0,34,56]
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m = 0
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for i in l1:
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if i>m:
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m = i
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print(m)
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import turtle
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turtle.title("多边形")
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turtle.bgcolor("black") # 设置背景颜色
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turtle.speed(0) # 设置画笔速度
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turtle.penup() # 抬笔
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turtle.pendown() # 落笔
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turtle.pencolor("white")# 设置画笔颜色
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a = turtle.numinput("边数","请问需要绘制几边形") #获取用户输入,得到的是浮点型数据
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a = int(a)#将变量a转换为整数类型
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b = turtle.numinput("花瓣数量","这朵花有几个花瓣")
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b = int(b)# 将b转换为整数
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for j in range(b):
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for i in range(a):
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turtle.forward(100)#前进
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turtle.left(360/a)#左转
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turtle.left(360/b)
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turtle.penup()
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turtle.mainloop()
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'''
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#print(round(132.56,-3))
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n = int(input())
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nums = []
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for i in range(n):
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a = int(input())
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nums.append(a)
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for i in nums:
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f=0
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for j in range(1,i+1):
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for k in range(1,i+1):
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if j*j + k*k == i:
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f = 1
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print("Yes")
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break
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if f == 1:
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break
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else:
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print("No")'''
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N = int(input())
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k = int(input())
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Sum = 0
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for i in range(1,N+1):
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for j in str(i):
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if j == str(k):
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Sum+=1
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print(Sum)
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t = int(input())
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b = []
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for i in range(t):
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n = int(input())
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a = input()
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a = [int(j) for j in a.split()]
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b.append(a)
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for i in range(t):
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m = max(b[i])
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for j in b[i]:
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if m%j != 0:
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break
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else:
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print("Yes")
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continue
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print("No")
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l1 = [6, 4, 2, 1, 5]#未排序
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for i in range(1,5):
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print(i)
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#第一次循环 i=1 key=4 j=0
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#第二次循环 i=2 key=2 j=1
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for i in range(1,len(l1)):
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key = l1[i]
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j = i-1
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# l1 [4,6,2,1,5]
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while j>=0 and key<l1[j]:
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l1[j+1] = l1[j]#右移
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# l1 [6,6,4,2,1,5]
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j=j-1
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l1[j+1] = key
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print(l1)
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l2 = [89,5,6,8,4,12,56,49,7]
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def fun(n):
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#print(n)
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if n == 1 or n==0:
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return n
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else:
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return fun(n-1) + fun(n-2)
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print(fun(8))
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# 基本情况 n==1 or n==0 返回n
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# 递归步骤 f(n) = f(n-1) + f(n-2)
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# 1,3,5,7,9,11......
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# 数列
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# 1,3,5,7,9
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def fibonacci(n):
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if n <= 1: # 基本情况:第1项和第2项都是1
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return n
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else: # 递归情况:第n项是前两项的和
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return fibonacci(n - 1) + fibonacci(n - 2)
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# n = 3
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# n = 2
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# n=1 结果1
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# n=0 结果0
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# 结果 1
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# n = 1 结果1
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# 结果 2
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print(fibonacci(6))
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# 阶乘 5的阶乘,5*4*3*2*1
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# 基本情况:n==1, 返回1
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# 递归过程:n*f(n-1)
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# 8的阶乘
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# ---------------------------------
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# n项的数列,1,2,3,4,5,6,7,8......
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# 使用递归求前n项数值的和
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# 基本情况:n==1
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# 递归过程:n+f(n-1)
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# 前10项的和
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# 基本情况:列表长度小于等于1
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# 递归过程:找中间值,与中间值进行比较,返回左,中,右连接后的结果
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l = [5,3,7,6,4,1]
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def fun(lst):
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if len(lst) <= 1:
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return lst
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else:
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mid = lst[0]
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print("当前中间值:",mid)
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left = []
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right = []
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for i in range(1,len(lst)):
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if lst[i] < mid:
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left.append(lst[i])
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else:
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right.append(lst[i])
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print("左侧列表:",left)
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print("右侧列表:", right)
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return fun(left)+[mid]+fun(right)
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fun(l)
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# 使用快速排序实现对以下列表的排序,[98,89,78,69,53,78,99]
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# 选择排序
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a = [5,2,1,8,9,2,6,7]
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for i in range(0,len(a)-1):
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min_i = i # 设置最小值所对应的位置
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for j in range(i+1, len(a)):
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if a[j] < a[min_i]:
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min_i = j # 更新最小值所对应的位置
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a[i],a[min_i] = a[min_i],a[i] # 交换第i项和第最小值项
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print(a)
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'''
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a = [5,2,1,8,9,2,6,7]
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第一轮
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i = 0 min_i = 0
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j = 1 a[1] < a[0]? min_i = 1
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j = 2 a[2] < a[1]? min_i = 2
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j = 3 a[3] < a[2]? min_i = 2
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j = 4 a[4] < a[2]? min_i = 2
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j = 5 a[5] < a[min_i]? min_i = 2
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j = 6 a[j] < a[min_i]? min_i = 2
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j = 7 a[j] < a[min_i]? min_i = 2
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a[i],a[min_i]交换 [1,2,5,8,9,2,6,7]
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i = 1 min_i = 1
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j = 2 a[j]<a[min_i]? min_i = 1
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...
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...
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'''
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@ -0,0 +1,16 @@
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# 这是一个示例 Python 脚本。
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# 按 Shift+F10 执行或将其替换为您的代码。
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# 按 双击 Shift 在所有地方搜索类、文件、工具窗口、操作和设置。
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def print_hi(name):
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# 在下面的代码行中使用断点来调试脚本。
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print(f'Hi, {name}') # 按 Ctrl+F8 切换断点。
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# 按间距中的绿色按钮以运行脚本。
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if __name__ == '__main__':
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print_hi('PyCharm')
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# 访问 https://www.jetbrains.com/help/pycharm/ 获取 PyCharm 帮助
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